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Definition 5.4.1
Let ≤ be an ordering relation in
a set X and let A be a subset of X.
An element x0
∈ X such that for every a ∈
A it holds that a ≤ x0
is an upper
bound of A.
Example 5.4.1
(1) Consider an ordered set <R, ≤ > and its subset A = {x ∈ R: 1< x < 2}. Upper bounds of the set A are the number 3 and every number greater than or equal 2. Lower bounds of the set A are the numbers 1, 0, -1, -2, and every number less than or equal 1, for each of them is smaller than any element of the set A.
(2) Consider the set of natural numbers ordered by the relation of divisibility | and the set B = {4,6,8}. The numbers 24, 48 and any number that divides by 4, 6 and 8 are upper bounds of the set B. Lower bounds of the set B are 1 and 2 since both 1 and 2 are divisors of 4, 6 and 8.
(3) Consider the set A of all rational numbers x such that x2are less that 2, as a subset of the set of real numbers ordered by the usual ordering. The lower bound of this set is the -square root of 2 and all less real numbers, and the upperbound is the +square root of 2 and all greater real numbers.
Definition 5.4.2
The least
upper bound (l.u.b.) or
supremum of a subset A of an
ordered set <X, ≤ > is
the element of X denoted sup A such that it is the least upper bound of
A if it exist.
x0 = sup A iff
The greatest lower bound (g.l.b.) or infimum of a subset A of an ordered set <X, ≤ > is the element of X denoted inf A such that it is the greatest lower bound of A if it exist.
x1 = inf A iff
Question 5.4.1: Let A be a subset of a partially ordered set. Is sup A equal to the greatest element of A?
----- See answer -----Example 5.4.2
Question 5.4.2 Consider an ordered set <P(X), ⊆ > and two subsets A, B ∈ P(X). Calculate the inf{A,B}.
----- See answer -----Problem 5.4.1
Let (Xi)i ∈ I be an indexed family of subsets of an ordered set < P(X), ⊆ >. Define the least upper bound of the family.
Answer : The generalized union of all sets of the family. Indeed, observe that Xi ⊆ ⎩⎭ i ∈ I Xi , since the generalized union ⎩⎭ i ∈ I Xi (c.f. 1.6) consists of all elements of all sets of the family.. Suppose that for a set B and for all i ∈ I, Xi ⊆ B and let x ∈ ⎩⎭ i ∈ I Xi . Then there exist k ∈ I, x ∈ Xk, therefore x ∈ B. We have proved that ⎩⎭ i ∈ I Xi ⊆ B. We conclude that the generalized union ⎩⎭ i ∈ I Xi is the least upper bound of the family of subsets (Xi)i ∈I.
In an analogous way one can prove that inf (Xi)i ∈ I = ⎧⎫ i ∈ I Xi.
One example of a lattice is the ordered set shown on Figure 5.2.1.
More generally, the set <P(X),
⊆ >, where X is an arbitrary set is a
lattice: for arbitrary subsets A and B of X, set-theoretical union is a
least upper bound and set-theoretical intersection is a geatest lower
bound.
Question 5.4.3 Consider the set of real numbers with the relation ≤. Is it a lattice or not?
----- See answer -----
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