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Theorem 9.6.1
For every set X, |X| < |2X|.
Proof.
If X is an empty set then the theorem is obviously true (|X|= 0 and |2 X| =1, see lecture 1).
Because we may construct a function g(x) = {x} which transforms the set X into P(X), namely into the family of one-element sets {{x}: x ∈ X}, then, of course, |X| ≤ |2X|.
Thus, it is enough to show that no subset of the set X is equipotent with 2X. Suppose for a contradiction that for some A ⊆ X there exists a bijection f : A → 2 X. Thus, for every a ∈ A, f(a) ⊆ X. Let Z = {a ∈ A : a ∉ f(a)}. Of course Z ⊆ X. Because the function f is a bijection onto the set of all subsets of X, then for some a0 ∈ A, f(a0) = Z. Let's consider two disjoint cases: the first case a0 ∈ Z, the second case a0 ∉ Z.
In the first case, from the assumption a0 ∈ Z and from the definition of Z, we obtain a0 ∉ f(a0), that is a0 ∉ Z. Contradiction.
In the second case, if a0 ∉ Z then a0 ∉ f(a0), as f(a0) = Z. Hence, according to the definition of the set Z, we obtain a0 ∈ Z. Contradiction.
Because both cases lead to a contradiction, therefore, the set Z cannot be ever constructed. In consequence, there is no set A or function f which is bijection from the set A onto the set 2 X. ♦
Remark The method used in
the proof of the theorem 9.6.1 is known as “diagonalization
argument”.
Cantor’s Theorem tells us that no matter how large a set we may have, we can always consider a set that is yet larger. Thus, it gives us the method for building infinite sets of different cardinal numbers.
All sets
have pairwise different powers. In particular, it follows that |N| < |2N|.
Another consequence of the Cantor's theorem is that the notion of
the set
of all sets is an inconsistent (we have studied this problem in the
lecture
1.6). Suppose for a contradiction, that such a set, denoted
here by X exists. Then for an arbitrary set A, the set of all subsets
of
set A is a subset of X, that is P(A) ⊆ X.
In
particular, P(X) ⊆ X. Therefore, |P(X)| ≤ |X|, but this contradicts the
Cantor's
theorem.
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